A thin rod of length 
lies along the axis of a concave mirror of focal length f. One end of its magnified image touches an end of the rod, the length of the image is-
Text Solution
Verified by ExpertsThe correct answer is:
B
u 1 = v 1 = 2f – (i)
u 2 = – 
= – 
v 2 = ? f = –f
by mirror formula
= 
– 
= 
+ 
= – 
v 2 = – 
Size of image = |v 2 | – |v 1 |
= 
– 2f = 
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